y=10 3y^2 + 10y + 5
asked by guest on Jan 14, 2025 at 9:50 pm
MathBot Answer:
3y2+10y+5=4053 {y}^{2} + 10 y + 5 = 4053y2+10y+5=405
3y2+10y+5=3⋅102+5+10⋅10=5+3⋅100+10⋅10=5+4⋅100=5+400=405\begin{aligned}3 y^{2} + 10 y + 5&=3 \cdot 10^{2} + 5 + 10 \cdot 10\\&=5 + 3 \cdot 100 + 10 \cdot 10\\&=5 + 4 \cdot 100\\&=5 + 400\\&=405\end{aligned}3y2+10y+5=3⋅102+5+10⋅10=5+3⋅100+10⋅10=5+4⋅100=5+400=405
