$6^{x}$ + 1 = 0
You asked:
Solve the equation \({6}^{x} + 1 = 0\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\pi}{\log{\left(6 \right)}} i \approx 1.7533562 i\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).
$6^{x}$ + 1 = 0
You asked:
MathBot Answer:
The solution is: \[x = \frac{\pi}{\log{\left(6 \right)}} i \approx 1.7533562 i\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).