\int _{-10}^{10}\:1+\frac{\left(e^{\frac{t}{10}}\:-\:e^{-\frac{t}{10}}\right)}{2}
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\int _{-10}^{10}\:1+\frac{\left(e^{\frac{t}{10}}\:-\:e^{-\frac{t}{10}}\right)}{2}
MathBot Answer:
MathBot is working on a solution to your problem.