slope -1/3 and y-intercept 2
You asked:
Find an equation of the line with slope \(-\frac{1}{3}\) and y-intercept \((0, 2)\).
MathBot Answer:
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{-1}{3} \\ A =& 1, B = 3 \end{aligned}$$$$\begin{aligned}1 x + 3 y + C &= 0 \\ 1(0) + 3(2) + C &= 0 \\ 0 + 6 + C &= 0 \\ 6 + C &= 0 \\ C &= -6 \end{aligned}$$An equation of the line in standard form is: $x + 3 y - 6 = 0$.
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= - \frac{1}{3}x + b \\ 2 &= - \frac{1}{3} \times 0 + b \\ 2 &= 0 + b \\ b &= 2 \end{aligned}$$The slope-intercept form of the line is: $y = - \frac{x}{3} + 2$.