y=x^2-1

asked by guest
on Nov 24, 2024 at 10:44 am



You asked:

Investigate the equation: \(y = {x}^{2} - 1\).

MathBot Answer:

The graph of the equation \(y = {x}^{2} - 1\) is a parabola.


The coordinates of its vertex are: \(\left(0, -1\right)\)

The coordinates of its focus are: \(\left(0, - \frac{3}{4}\right)\)

The directrix has equation: \(4 y + 5 = 0\).

The parabola has parameterization: \[\begin{aligned}x\left(\theta\right) &= \theta\\y\left(\theta\right) &= -1 + \theta^{2}\end{aligned}\]