x^2-xy+b^2=3
x+2y+1=0
You asked:
Solve the system of equations:\[\begin{aligned}{x}^{2} - x y + {b}^{2} &= 3\\x + 2 y + 1 &= 0\end{aligned}\]
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}b &= \sqrt{- 6 y^{2} - 5 y + 2}\\x &= - 2 y - 1\end{aligned}$$\(y\) is a free variable.