$$\int(2x^2+4x-3/x^2) dx$$
You asked:
Evaluate the integral: \(\int{2 {x}^{2} + 4 x - \frac{3}{{x}^{2}}}dx\)
MathBot Answer:
Antiderivative
\[\int{2 {x}^{2} + 4 x - \frac{3}{{x}^{2}}}dx = 2 x^{2} + \frac{3}{x} + \frac{2 x^{3}}{3} + C\]
$$\int(2x^2+4x-3/x^2) dx$$
You asked:
MathBot Answer:
\[\int{2 {x}^{2} + 4 x - \frac{3}{{x}^{2}}}dx = 2 x^{2} + \frac{3}{x} + \frac{2 x^{3}}{3} + C\]