∫(2x2+4x−3/x2)dx\int(2x^2+4x-3/x^2) dx

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on Nov 26, 2024 at 7:52 pm



You asked:

Evaluate the integral: ∫2x2+4x−3x2dx\int{2 {x}^{2} + 4 x - \frac{3}{{x}^{2}}}dx

MathBot Answer:

Antiderivative

∫2x2+4x−3x2dx=2x2+3x+2x33+C\int{2 {x}^{2} + 4 x - \frac{3}{{x}^{2}}}dx = 2 x^{2} + \frac{3}{x} + \frac{2 x^{3}}{3} + C

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