∑i=1n5(−1)n(n−5)\sum_{i=1}^{n}{5(-1)^n(n-5)}i=1∑n5(−1)n(n−5)
asked by guest on Nov 13, 2024 at 8:38 pm
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MathBot Answer:
∑i=1n5(−1)n(n−5)=5(−1)n(n−5)n\sum_{i=1}^{n} 5 \left(-1\right)^{n \left(n - 5\right)} = 5 \left(-1\right)^{n \left(n - 5\right)} ni=1∑n5(−1)n(n−5)=5(−1)n(n−5)n
