∑i=1n5(−1)n(n−5)\sum_{i=1}^{n}{5(-1)^n(n-5)}

asked by guest
on Nov 13, 2024 at 8:38 pm



You asked:

Evaluate the expression: ∑i=1n5(−1)n(n−5)\sum_{i = 1}^{n} {5 {\left( -1 \right)}^{n \left(n - 5\right)}}

MathBot Answer:

∑i=1n5(−1)n(n−5)=5(−1)n(n−5)n\sum_{i=1}^{n} 5 \left(-1\right)^{n \left(n - 5\right)} = 5 \left(-1\right)^{n \left(n - 5\right)} n

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