solve the following integral

(sin x − 3 cos x +2x + sec x tan x − sec2 x +x^2 + 1) dx

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on Nov 27, 2024 at 4:44 pm



You asked:

Evaluate the expression: ∫sin⁡(x)−3cos⁡(x)+2x+sec⁡(x)tan⁡(x)−sec⁡(2)⋅x+x2+1dx\int{\sin\left( x \right) - 3 \cos\left( x \right) + 2 x + \sec\left( x \right) \tan\left( x \right) - \sec\left( 2 \right) \cdot x + {x}^{2} + 1}dx

MathBot Answer:

Simplified: ∫sin⁡(x)−3cos⁡(x)+2x+sec⁡(x)tan⁡(x)−sec⁡(2)⋅x+x2+1dx=x33+x2−x2sec⁡(2)2+x−3sin⁡(x)−cos⁡(x)+1cos⁡(x)\int{\sin\left( x \right) - 3 \cos\left( x \right) + 2 x + \sec\left( x \right) \tan\left( x \right) - \sec\left( 2 \right) \cdot x + {x}^{2} + 1}dx = \frac{x^{3}}{3} + x^{2} - \frac{x^{2} \sec{\left(2 \right)}}{2} + x - 3 \sin{\left(x \right)} - \cos{\left(x \right)} + \frac{1}{\cos{\left(x \right)}}

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