nn−2n^{n-2} *( n2n^{2} -2*n*n+n*n-n)* e−ne^{-n}

asked by guest
on Nov 16, 2024 at 11:40 am



You asked:

Evaluate the expression: nn−2(n2−2n⋅n+n⋅n−n)⋅e−n{n}^{n - 2} \left({n}^{2} - 2 n \cdot n + n \cdot n - n\right) \cdot {e}^{-n}

MathBot Answer:

Evaluated



nn−2(n2−2n⋅n+n⋅n−n)⋅e−n=−nn−2ne−n\displaystyle {n}^{n - 2} \left({n}^{2} - 2 n \cdot n + n \cdot n - n\right) \cdot {e}^{-n} = - n^{n - 2} n e^{- n}

Expanded

nn−2(n2−2n⋅n+n⋅n−n)⋅e−n=−nne−nn{n}^{n - 2} \left({n}^{2} - 2 n \cdot n + n \cdot n - n\right) \cdot {e}^{-n} = - \frac{n^{n} e^{- n}}{n}

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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