2-5(mod8)
You asked:
Evaluate \(2 - 5\) modulo \(8\)
MathBot Answer:
\[2 - 5 \bmod 8 = 5\]
Given two numbers \(a\) and \(n\), \(a\) modulo \(n\) (often written \(a \bmod n\)) is the remainder when \(a\) is divided by \(n\).
\(\dfrac{2 - 5}{8} = \dfrac{-3}{8} = -1\) with remainder \(5\)
Therefore \(2 - 5 \bmod 8 = 5\)