2-5(mod8)

asked by guest
on Sep 23, 2024 at 10:16 am



You asked:

Evaluate \(2 - 5\) modulo \(8\)

MathBot Answer:

\[2 - 5 \bmod 8 = 5\]


Given two numbers \(a\) and \(n\), \(a\) modulo \(n\) (often written \(a \bmod n\)) is the remainder when \(a\) is divided by \(n\).

\(\dfrac{2 - 5}{8} = \dfrac{-3}{8} = -1\) with remainder \(5\)
Therefore \(2 - 5 \bmod 8 = 5\)