2x^2-4xy-2y^2

asked by guest
on Apr 07, 2025 at 6:40 am



You asked:

Evaluate the expression: 2x2−4xy−2y22 {x}^{2} - 4 x y - 2 {y}^{2}

MathBot Answer:

2x2−4xy−2y2=2x2−4xy−2y22 {x}^{2} - 4 x y - 2 {y}^{2} = 2 x^{2} - 4 x y - 2 y^{2}

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