Let S = {n ∈ N ; (x + y) + n = x + (y + n) for all x, y ∈ N}.
(a) Prove, using the definition of sum of natural numbers, that 0 ∈ S
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Let S = {n ∈ N ; (x + y) + n = x + (y + n) for all x, y ∈ N}.
(a) Prove, using the definition of sum of natural numbers, that 0 ∈ S
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.