y=1/1(v/c)2y=1/\sqrt1-(v/c)^{2}

asked by guest
on Nov 24, 2024 at 3:09 pm



You asked:

Investigate the equation: y=11(vc)2y = \frac{1}{\sqrt{1}} - {\left( \frac{v}{c} \right)}^{2}.