$\frac{\x+3}{\x+2}$ + $\frac{\x-3}{\x-2}$ = $\frac{\2x-3}{\x-1}$

asked by guest
on Mar 17, 2025 at 6:30 am



You asked:

Solve the equation x+3x+2+x−3x−2=2x−3x−1\frac{x + 3}{x + 2} + \frac{x - 3}{x - 2} = \frac{2 x - 3}{x - 1} for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=0x=4\begin{aligned}x &= 0\\x &= 4\end{aligned}

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