cos(npi/2)=0
You asked:
Solve the equation \(\cos\left( \frac{n \cdot \pi}{2} \right) = 0\) for the variable \(n\).
MathBot Answer:
The principal value in \(0 \le n \le 2\) is \(n \approx 1.0\)
The real solutions are: \[\begin{aligned}n &= \left\{1 + 4 n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{4.0 n + 1.0\; \middle|\; n \in \mathbb{Z}\right\}\\n &= \left\{3 + 4 n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{4.0 n + 3.0\; \middle|\; n \in \mathbb{Z}\right\}\end{aligned}\]