2^x + x =5
asked by guest on Nov 15, 2024 at 3:28 am
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MathBot Answer:
The solution is: x=−2.27655822861956804859615928132903999692740923644+5log(2)log(2)≈1.7156207x = \frac{-2.27655822861956804859615928132903999692740923644 + 5 \log{\left(2 \right)}}{\log{\left(2 \right)}} \approx 1.7156207x=log(2)−2.27655822861956804859615928132903999692740923644+5log(2)≈1.7156207