48kg/(1+9.8(m/s^2))

asked by guest
on Sep 22, 2024 at 1:44 am



You asked:

Evaluate the expression: \(\frac{48 k g}{1 + 9.8 \cdot \frac{m}{{s}^{2}}}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{48 k g}{1 + 9.8 \cdot \frac{m}{{s}^{2}}} = \frac{48 g k}{\frac{49 m}{5 s^{2}} + 1} \)

Expanded

\[\frac{48 k g}{1 + 9.8 \cdot \frac{m}{{s}^{2}}} = \frac{48 g k}{\frac{49 m}{5 s^{2}} + 1}\]

Factored

\[\frac{48 k g}{1 + 9.8 \cdot \frac{m}{{s}^{2}}} = \frac{240 s^{2} g k}{49 m + 5 s^{2}}\]

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