(2a-a²)*(a³-3)
asked by guest on Mar 30, 2025 at 11:18 pm
You asked:
MathBot Answer:
(2a−a2)(a3−3)=(−a2+2a)(a3−3)\displaystyle \left(2 a - {a}^{2}\right) \left({a}^{3} - 3\right) = \left(- a^{2} + 2 a\right) \left(a^{3} - 3\right) (2a−a2)(a3−3)=(−a2+2a)(a3−3)
(2a−a2)(a3−3)=−a5+2a4+3a2−6a\left(2 a - {a}^{2}\right) \left({a}^{3} - 3\right) = - a^{5} + 2 a^{4} + 3 a^{2} - 6 a(2a−a2)(a3−3)=−a5+2a4+3a2−6a
(2a−a2)(a3−3)=−a(a3−3)(a−2)\left(2 a - {a}^{2}\right) \left({a}^{3} - 3\right) = - a \left(a^{3} - 3\right) \left(a - 2\right)(2a−a2)(a3−3)=−a(a3−3)(a−2)
