Math Problem Solver

\[ 6\frac{2}{7} + 2\frac{3}{7} = \frac{61}{7} = 8.\overline{714285} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{6}{1}\), \(\frac{2}{7}\), \(\frac{2}{1}\), and \(\frac{3}{7}\) is \(7\). \[ \begin{aligned} 6\frac{2}{7} + 2\frac{3}{7} &= \frac{6 \cdot 7}{1 \cdot 7} + \frac{2 \cdot 1}{7 \cdot 1} + \frac{2 \cdot 7}{1 \cdot 7} + \frac{3 \cdot 1}{7 \cdot 1} \\ &= \frac{42 + 2 + 14 + 3}{7} \\ &= \frac{61}{7} \end{aligned} \]