(20+1)/10^((2-6/2)+1)
You asked:
Evaluate the expression: \(\frac{20 + 1}{{10}^{2 - \frac{6}{2} + 1}}\)
MathBot Answer:
\[\frac{20 + 1}{{10}^{2 - \frac{6}{2} + 1}} = 21\]
\[\begin{aligned}\frac{20 + 1}{{10}^{2 - \frac{6}{2} + 1}}& = \left(20 + 1\right) \cdot \frac{1}{10^{2 - 3 + 1}}\\& = 21 \cdot \frac{1}{10^{2 - 3 + 1}}\\& = 21 \cdot \frac{1}{10^{-1 + 1}}\\& = 21 \cdot \frac{1}{10^{0}}\\& = \frac{21}{1}\\& = 21\end{aligned}\]