Math Problem Solver

\[ 2\frac{1}{3} + 1\frac{1}{2} = \frac{23}{6} = 3.8\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{1}{3}\), \(\frac{1}{1}\), and \(\frac{1}{2}\) is \(6\). \[ \begin{aligned} 2\frac{1}{3} + 1\frac{1}{2} &= \frac{2 \cdot 6}{1 \cdot 6} + \frac{1 \cdot 2}{3 \cdot 2} + \frac{1 \cdot 6}{1 \cdot 6} + \frac{1 \cdot 3}{2 \cdot 3} \\ &= \frac{12 + 2 + 6 + 3}{6} \\ &= \frac{23}{6} \end{aligned} \]