625P^4+1150P^2−1920P+657=0

asked by guest
on Nov 17, 2024 at 8:25 pm



You asked:

Solve the equation \(625 \cdot {P}^{4} + 1150 \cdot {P}^{2} - 1920 P + 657 = 0\) for the variable \(P\).

MathBot Answer:

The 3 solutions to the equation are: \[\begin{aligned}P &= \frac{3}{5} = 0.6\\P &= - \frac{3}{5} - \frac{8 i}{5} = -0.6 -1.6 i\\P &= - \frac{3}{5} + \frac{8 i}{5} = -0.6 + 1.6 i\end{aligned}\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).