(2x-2)/(x-3)
asked by guest on Apr 09, 2025 at 8:34 pm
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MathBot Answer:
2x−2x−3=2x−2x−3\displaystyle \frac{2 x - 2}{x - 3} = \frac{2 x - 2}{x - 3} x−32x−2=x−32x−2
2x−2x−3=2xx−3−2x−3\frac{2 x - 2}{x - 3} = \frac{2 x}{x - 3} - \frac{2}{x - 3}x−32x−2=x−32x−x−32
2x−2x−3=2(x−1)x−3\frac{2 x - 2}{x - 3} = \frac{2 \left(x - 1\right)}{x - 3}x−32x−2=x−32(x−1)