3x^(2)-10x+8 is a perfect square

asked by guest
on Jan 22, 2025 at 5:49 pm



You asked:

Is \(3 x^{2} - 10 x + 8\) a square number?

MathBot Answer:

\(3 x^{2} - 10 x + 8\) is not a square number.

A square number is a number that is the square of an integer. If \(x^2 = y\) for any integer \(x\), then \(y\) is a square number.

\[\sqrt{3 x^{2} - 10 x + 8} = \sqrt{3 x^{2} - 10 x + 8}\] There is no integer that satisfies \(x^2=3 x^{2} - 10 x + 8\), therefore \(3 x^{2} - 10 x + 8\) is not a square number.

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