√2x+4+1=5
You asked:
Solve the equation \(\sqrt{2} \cdot x + 4 + 1 = 5\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = 0\]
\[\begin{aligned}\sqrt{2} \cdot x + 4 + 1 &= 5\\\sqrt{2} x + 5 &= 5\\\sqrt{2} x &= 0\\x &= 0\end{aligned}\]