\(y-3y^{7}=\left(y^{6}+6x\right)y^{\prime }\)

asked by guest
on Sep 18, 2024 at 7:00 pm



You asked:

Investigate the equation: \(y - 3 \cdot {y}^{7} = \left({y}^{6} + 6 x\right) \cdot y^{\prime}\).

MathBot Answer:

\[\frac{\left(-1 + 3 y^{6}{\left(x \right)}\right) x}{y^{6}{\left(x \right)}} + C_{1} + \log{\left(y{\left(x \right)} \right)} = 0\]

\(C_{1}\) is an arbitrary constant.