Math Problem Solver

\[ 1\frac{1}{2} + 1\frac{1}{8} + 1\frac{1}{4} = \frac{31}{8} = 3.875 \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{1}{1}\), \(\frac{1}{2}\), \(\frac{1}{1}\), \(\frac{1}{8}\), \(\frac{1}{1}\), and \(\frac{1}{4}\) is \(8\). \[ \begin{aligned} 1\frac{1}{2} + 1\frac{1}{8} + 1\frac{1}{4} &= \frac{1 \cdot 8}{1 \cdot 8} + \frac{1 \cdot 4}{2 \cdot 4} + \frac{1 \cdot 8}{1 \cdot 8} + \frac{1 \cdot 1}{8 \cdot 1} + \frac{1 \cdot 8}{1 \cdot 8} + \frac{1 \cdot 2}{4 \cdot 2} \\ &= \frac{8 + 4 + 8 + 1 + 8 + 2}{8} \\ &= \frac{31}{8} \end{aligned} \]