(√a - √x)^4 / √ax
asked by guest on Nov 15, 2024 at 4:06 am
You asked:
MathBot Answer:
(a−x)4a⋅x=(a−x)4ax\displaystyle \frac{{\left( \sqrt{a} - \sqrt{x} \right)}^{4}}{\sqrt{a} \cdot x} = \frac{\left(\sqrt{a} - \sqrt{x}\right)^{4}}{\sqrt{a} x} a⋅x(a−x)4=ax(a−x)4
(a−x)4a⋅x=a32x+6a−4x−4ax+xa\frac{{\left( \sqrt{a} - \sqrt{x} \right)}^{4}}{\sqrt{a} \cdot x} = \frac{a^{\frac{3}{2}}}{x} + 6 \sqrt{a} - 4 \sqrt{x} - \frac{4 a}{\sqrt{x}} + \frac{x}{\sqrt{a}}a⋅x(a−x)4=xa23+6a−4x−x4a+ax
