-3/3(a+c(b+5)-(-6+a)) given a=1, b=-6, c=-4

asked by guest
on Jul 26, 2024 at 2:14 pm



MathBot Answer:

\[\frac{-3}{3 \cdot \left(a + c \cdot \left(b + 5\right) - \left(-6 + a\right)\right)} = \frac{-3}{3 \cdot \left(1 + -4 \cdot \left(-6 + 5\right) - \left(-6 + 1\right)\right)} = - \frac{1}{10}\]

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