-3/3(a+c(b+5)-(-6+a)) given a=1, b=-6, c=-4
MathBot Answer:
\[\frac{-3}{3 \cdot \left(a + c \cdot \left(b + 5\right) - \left(-6 + a\right)\right)} = \frac{-3}{3 \cdot \left(1 + -4 \cdot \left(-6 + 5\right) - \left(-6 + 1\right)\right)} = - \frac{1}{10}\]