χ=−μ0e26m⟨r2⟩,\chi = -\frac{\mu_0 e^2}{6m} \langle r^2 \rangle,
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
χ=−μ0e26m⟨r2⟩,\chi = -\frac{\mu_0 e^2}{6m} \langle r^2 \rangle,
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.