1500=1120÷ke-0.0

asked by guest
on Nov 24, 2024 at 7:02 pm



You asked:

Investigate the equation: \(1500 = \frac{1120}{k e} - 0.0\).

MathBot Answer:

The solution is: \[k = \frac{56}{75 e} \approx 0.27468332\]

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

+ Submit Question