Es sei S9 die symmetrische Gruppe auf {1, 2, 3, 4, 5, 6, 7, 8, 9}.

Schreiben Sie σ = (3 1 4)(1 5 9 2 6)(5 3) ∈ S9 als Produkt paarweise disjunkter Zykel.

asked by guest
on Nov 20, 2024 at 3:30 am



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