x/y=1/3then value of x^2+y^2/x^2-y^2

asked by guest
on Jan 24, 2025 at 10:13 pm



MathBot Answer:

x2y2+y2x2=98y29x^{2} - y^{2} + \frac{y^{2}}{x^{2}} = 9 - \frac{8 y^{2}}{9}


xy=13\frac{x}{y} = \frac{1}{3}Solve for xx: x=y3x = \frac{y}{3}Substitute xx into the given expression: x2y2+y2x2=y2+y2(y3)2+(y3)2x2y2+y2x2=98y29\begin{aligned}x^{2} - y^{2} + \frac{y^{2}}{x^{2}} &= - y^{2} + \frac{y^{2}}{\left(\frac{y}{3}\right)^{2}} + \left(\frac{y}{3}\right)^{2} \\ x^{2} - y^{2} + \frac{y^{2}}{x^{2}} &= 9 - \frac{8 y^{2}}{9}\end{aligned}