x/y=1/3then value of x^2+y^2/x^2-y^2
asked by guest on Jan 24, 2025 at 10:13 pm
MathBot Answer:
x2−y2+y2x2=9−8y29x^{2} - y^{2} + \frac{y^{2}}{x^{2}} = 9 - \frac{8 y^{2}}{9}x2−y2+x2y2=9−98y2
xy=13\frac{x}{y} = \frac{1}{3}yx=31Solve for xxx: x=y3x = \frac{y}{3}x=3ySubstitute xxx into the given expression: x2−y2+y2x2=−y2+y2(y3)2+(y3)2x2−y2+y2x2=9−8y29\begin{aligned}x^{2} - y^{2} + \frac{y^{2}}{x^{2}} &= - y^{2} + \frac{y^{2}}{\left(\frac{y}{3}\right)^{2}} + \left(\frac{y}{3}\right)^{2} \\ x^{2} - y^{2} + \frac{y^{2}}{x^{2}} &= 9 - \frac{8 y^{2}}{9}\end{aligned}x2−y2+x2y2x2−y2+x2y2=−y2+(3y)2y2+(3y)2=9−98y2