5000*n^2 - 200*n + 1

factorize

asked by guest
on Nov 25, 2024 at 7:13 am



You asked:

Factor the expression: \(\displaystyle 5000 {n}^{2} - 200 n + 1\)

MathBot Answer:

Factorization over the real numbers:

\[5000 \cdot \left(1 n^{2} - 0.04 n + 0.0002\right)\]

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