(2y-3) 2^{2}2
asked by guest on Mar 25, 2025 at 10:20 pm
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MathBot Answer:
(2y−3)2=(2y−3)2\displaystyle {\left( 2 y - 3 \right)}^{2} = \left(2 y - 3\right)^{2} (2y−3)2=(2y−3)2
(2y−3)2=4y2−12y+9{\left( 2 y - 3 \right)}^{2} = 4 y^{2} - 12 y + 9(2y−3)2=4y2−12y+9