P = -1.1832Q + 90.436

asked by guest
on Nov 17, 2024 at 11:31 am



You asked:

Investigate the equation: \(P = -\left( 1.1832 Q \right) + 90.436\).

MathBot Answer:

The graph of \(P = -\left( 1.1832 Q \right) + 90.436\) is a line.

The P-intercept is \(\frac{22609}{250}\).

The Q-intercept is \(\frac{113045}{1479}\).

The slope of the line is \(- \frac{1250}{1479}\).

The slope-intercept form of the line is \(Q = \frac{113045}{1479} - \frac{1250 P}{1479}\).

The line in standard form is \( 1250 P + 1479 Q - 113045 = 0 \)