f(1)=2(200/3500)−1^2(1+cos(1×0.8))−0.2

asked by guest
on Nov 24, 2024 at 9:53 am



You asked:

Investigate the relation \(f\left( 1 \right) = 2 \cdot \frac{200}{3500} - {1}^{2} \cdot \left(1 + \cos\left( 1 \cdot 0.8 \right)\right) - 0.2\).

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