f (x, y) = x−2y + ln √(x^2 + y^2) + 3 arctan y/x

asked by guest
on Jan 26, 2025 at 11:48 pm



You asked:

Investigate the relation f(x,y)=x−2y+ln⁡(x2+y2)+3arctan⁡(y)xf\left( x, y \right) = x - 2 y + \ln\left( \sqrt{{x}^{2} + {y}^{2}} \right) + \frac{3 \arctan\left( y \right)}{x}.

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