-3,2,-8,-3,13 whats next

asked by guest
on Sep 22, 2024 at 6:35 am



MathBot Answer:

$$-3,2,-8,-3,13,...$$The next term in this recurrent sequence is $a_{6}=- \frac{406}{15}$.


The nth term in this sequence is given by the formula:

Recursive Formula: $$a_n=- \frac{26 a_{n-1}}{15} - \frac{37 a_{n-2}}{15} - \frac{179}{15}, \text{where } a_{1}=-3 \text{ and } a_{2}=2$$


RECURSIVE FORMULA

Linear Recurrence Relation

[View Steps]

Given a sequence of m terms, the recursive formula is of the form $$a_n=x_0 + x_1 a_{n-1} + ... + x_k a_{n-k}, \text{where } 1 \leq k \leq \left \lfloor \frac{m-1}{2} \right \rfloor$$

Using all the given terms, solve the systems of equations for $x_i$ when $k=1,...,\left \lfloor \frac{m-1}{2} \right \rfloor$. If $x_i$ is not found for any $k$, a recursive formula cannot be found using this method.


When $k=1$: $$a_n=x_0 + x_1 a_{n-1}, n > 1$$ Solve for $x_0$ and $x_1$: $$\begin{aligned} a_2&=x_0 + x_1 a_1 \\ a_3&=x_0 + x_1 a_2 \\ \vdots \\ a_m&=x_0 + x_1 a_{m-1}\end{aligned}$$