63-7p^2
asked by guest on Mar 31, 2025 at 1:10 pm
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MathBot Answer:
63−7p2=63−7p2\displaystyle 63 - 7 {p}^{2} = 63 - 7 p^{2} 63−7p2=63−7p2
63−7p2=−7(p−3)(p+3)63 - 7 {p}^{2} = - 7 \left(p - 3\right) \left(p + 3\right)63−7p2=−7(p−3)(p+3)