$$\sum_{k=1}^{n}{log(k+1/k)=log(n+1)}$$
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$$\sum_{k=1}^{n}{log(k+1/k)=log(n+1)}$$
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Below are 10 similar questions that I was able to parse.
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