f(x)=−5I
{x>2}
(x)+xI
{x<−1}
(x) when
x=3
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
f(x)=−5I
{x>2}
(x)+xI
{x<−1}
(x) when
x=3
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.