solve for 1-tan^2x / 1+tan^2x
asked by guest on Jan 22, 2025 at 12:59 pm
You asked:
MathBot Answer:
1−tan(x)21+tan(x)2=11 - \frac{{\tan\left( x \right)}^{2}}{1} + {\tan\left( x \right)}^{2} = 11−1tan(x)2+tan(x)2=1