solve for 1-tan^2x / 1+tan^2x
You asked:
Evaluate the expression: \(1 - \frac{{\tan\left( x \right)}^{2}}{1} + {\tan\left( x \right)}^{2}\)
MathBot Answer:
\[1 - \frac{{\tan\left( x \right)}^{2}}{1} + {\tan\left( x \right)}^{2} = 1\]
solve for 1-tan^2x / 1+tan^2x
You asked:
MathBot Answer:
\[1 - \frac{{\tan\left( x \right)}^{2}}{1} + {\tan\left( x \right)}^{2} = 1\]