solve for 1-tan^2x / 1+tan^2x

asked by guest
on Jan 22, 2025 at 12:59 pm



You asked:

Evaluate the expression: 1−tan⁡(x)21+tan⁡(x)21 - \frac{{\tan\left( x \right)}^{2}}{1} + {\tan\left( x \right)}^{2}

MathBot Answer:

1−tan⁡(x)21+tan⁡(x)2=11 - \frac{{\tan\left( x \right)}^{2}}{1} + {\tan\left( x \right)}^{2} = 1

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