∫02x(y2e−x2)dy\int_{0}^{2x}(y^2e^{-x^2}) dy

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on Apr 13, 2025 at 12:53 pm



You asked:

Evaluate the integral: ∫02xy2e−x2dy\int_{0}^{2 x}{{y}^{2} {e}^{-{x}^{2}}}dy

MathBot Answer:

∫02xy2e−x2dy=8x3e−x23\int_{0}^{2 x}{{y}^{2} {e}^{-{x}^{2}}}dy = \frac{8 x^{3} e^{- x^{2}}}{3}

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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