-1/8.55E-4ln[-ln(0.3046)]=

asked by guest
on Nov 26, 2024 at 12:35 pm



You asked:

Evaluate the expression: \(\frac{-1}{8.55 E} - 4 \ln\left( -\ln\left( 0.3046 \right) \right)\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{-1}{8.55 E} - 4 \ln\left( -\ln\left( 0.3046 \right) \right) = - 4 \log{\left(- \log{\left(\frac{1523}{5000} \right)} \right)} - \frac{20}{171 E} \)

Expanded

\[\frac{-1}{8.55 E} - 4 \ln\left( -\ln\left( 0.3046 \right) \right) = - 4 \log{\left(- \log{\left(3046 \right)} + 4 \log{\left(10 \right)} \right)} - \frac{20}{171 E}\]

Factored

\[\frac{-1}{8.55 E} - 4 \ln\left( -\ln\left( 0.3046 \right) \right) = - \frac{4 \cdot \left(171 E \log{\left(- \log{\left(3046 \right)} + 4 \log{\left(10 \right)} \right)} + 5\right)}{171 E}\]

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