-x^5-x^3+8x^2-8 Factorize
You asked:
Factor the expression: \(\displaystyle -{x}^{5} - {x}^{3} + 8 \cdot {x}^{2} - 8\)
MathBot Answer:
Factorization over the real numbers:
\[- 8 \cdot \left(0.125 x^{5} + 0.125 x^{3} - x^{2} + 1\right)\]Factorization over the complex numbers:
\[- \left(x + 0.909882606791041\right) \left(x - \left(1.34674501669168 + 0.133585352501592 i\right)\right) \left(x - \left(1.34674501669168 - 0.133585352501592 i\right)\right) \left(x + \left(0.891803713296156 - 2.00128312232431 i\right)\right) \left(x + \left(0.891803713296156 + 2.00128312232431 i\right)\right)\]Some linear factors are approximate.
\(i\) is the imaginary unit, defined as \(i^2 = -1\).