Math Problem Solver

\[ \frac{3}{7} + 6 + \frac{2}{7} = \frac{47}{7} = 6.\overline{714285} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{7}\), \(\frac{6}{1}\), and \(\frac{2}{7}\) is \(7\). \[ \begin{aligned} \frac{3}{7} + 6 + \frac{2}{7} &= \frac{3 \cdot 1}{7 \cdot 1} + \frac{6 \cdot 7}{1 \cdot 7} + \frac{2 \cdot 1}{7 \cdot 1} \\ &= \frac{3 + 42 + 2}{7} \\ &= \frac{47}{7} \end{aligned} \]