64 e^{-8x^2} (1 - 8x) = 0.

asked by guest
on Nov 15, 2024 at 5:03 am



You asked:

Investigate the equation: \(64 \cdot {e}^{-\left( 8 \cdot {x}^{2} \right)} \cdot \left(1 - 8 x\right) = 0\).

MathBot Answer:

The solution is: \[x = \frac{1}{8} = 0.125\]

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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