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C(n+2,r)=C(n,r)+2·C(n,r−1)+C(n,r−2)
asked by
guest
on Mar 22, 2025 at 5:34 pm
You asked:
Investigate the equation:
C
(
n
+
2
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r
)
=
C
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n
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r
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+
2
⋅
C
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n
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r
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1
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+
C
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n
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r
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2
)
C\left( n + 2, r \right) = C\left( n, r \right) + 2 \cdot C\left( n, r - 1 \right) + C\left( n, r - 2 \right)
C
(
n
+
2
,
r
)
=
C
(
n
,
r
)
+
2
⋅
C
(
n
,
r
−
1
)
+
C
(
n
,
r
−
2
)
.
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